Does Go allow a function to use another function as a parameter? -

the problem happening @ line 17 in go code. below program in python , go can see i'm attempting do. python works, go attempts have failed. read golang.org back, , google turned nothing, well.

def my_filter(x):   if x % 5 == 0:     return true   return false  #function returns list of numbers satisfy filter def my_finc(z, my_filter):    = []   x in z:     if my_filter(x) == true:       a.append(x)   return  print(my_finc([10, 4, 5, 17, 25, 57, 335], my_filter)) 

now, go version i'm having troubles with:

package main  import "fmt"  func filter(a []int) bool {     var z bool     := 0; < len(a); i++ {         if a[i]%5 == 0 {             z = true         } else {             z = false         }     }     return z }  func finc(b []int, filter) []int {     var c []int     := 0; < len(c); i++ {         if filter(b) == true {             c = append(c, b[i])         }     }     return c }  func main() {     fmt.println(finc([]int{1, 10, 2, 5, 36, 25, 123}, filter)) } 

yes, go can have functions parameters:

package main  import "fmt"  func myfilter(a int) bool {     return a%5 == 0 }  type filter func(int) bool  func finc(b []int, filter filter) []int {     var c []int     _, := range b {         if filter(i) {             c = append(c, i)         }     }     return c }  func main() {     fmt.println(finc([]int{1, 10, 2, 5, 36, 25, 123}, myfilter)) } 

the key need type pass in.

type filter func(int) bool 

i cleaned bit of code make more idiomatic. replaced loops range clauses.

for := 0; < len(b); i++ {     if filter(b[i]) == true {         c = append(c, b[i])     } } 

becomes

for _, := range b {     if filter(i) {         c = append(c, i)     } }