Bash script that creates a bash script with variables -

i'm writing bash called "newproject" creates second bash script called "compile". both scripts must able take arguments input. problem can not write "$1" compile script - copies contents of newproject's first argument compile script. part of newproject script creates compile script.

echo "#!/bin/bash" > $1/compile echo " if [[ -z '$1' ]];         echo "you missing file names. type in: compile -o executable files."         exit 1 fi" >> $1/compile chmod u+x $1/compile 

and here output test run of newproject script.

#!/bin/bash  if [[ -z 'testproject4' ]];          echo missing file names. type in: compile -o executable files.         exit 1 fi 

how can change newproject script instead of 'testproject4', compile script contains '$1'?

i use heredoc

cat <<'end' > "$1"/compile #!/bin/bash  if [[ -z $1 ]];         echo "you missing file names. type in: compile -o executable files."         exit 1 fi end chmod u+x "$1"/compile 

when quote heredoc terminator word (cat <<'end'), quotes entire doc