date - Converting the number of days in a month in Python? -

new python, , i'm writing program has user enter month (in terms of number, not word - e.g. "3" not "march"), , year (as in "2014"). want program display number of days in month entered , year. if user enters month 3 , year 2005, should display:

march 2005 has 31 days.

here's code:

def enteredmonth():     month = int(input("enter month in terms of number: "))     return month  def enteredyear():     year = int(input("enter year: "))     return int(year)  def leapyear(year):     if year % 4 == 0:         return true     else:         return false  def numberofdays(month):     if enteredmonth() == 1:         month = "january"         print ("31")     elif enteredmonth() == 2:         month = "february"         print ("28")     elif enteredmonth() == 2 , leapyear() == true:         month = "february"         print ("29")     elif enteredmonth() == 3:         month = "march"         print ("31")     elif enteredmonth() == 4:         month = "april"         print ("30")     elif enteredmonth() == 5:         month = "may"         print ("31")     elif enteredmonth() == 6:         month = "june"         print ("30")     elif enteredmonth() == 7:         month = "july"         print ("31")     elif enteredmonth() == 8:         month = "august"         print ("31")     elif enteredmonth() == 9:         month = "september"         print ("30")     elif enteredmonth() == 10:         month = "october"         print ("31")     elif enteredmonth() == 11:         month = "november"         print ("30")     elif enteredmonth() == 12:         month = "december"         print ("31")     else:         print("please enter valid month")  def main():    enteredmonth()    enteredyear()    leapyear(year)    numberofdays(month)    print(month, enteredyear(), "has", numberofdays(month) , "days")  if __name__ == '__main__':     main() 

the problem instead of getting proper format, i'm getting like:

3 2005 has none days.

please help! appreciate it.

i don't disagree ys-l's answer. i'm submitting 1 show better formatting mean.

def enteredmonth():     month = int(input("enter month in terms of number: "))     return month  def enteredyear():     year = int(input("enter year: "))     return int(year)  def leapyear(year):     if year % 4 == 0:         return true     else:         return false  def numberofdays(month):     if month == 1:         return 31     elif month == 2:         return 28     # etc. actually, pythonic implementation use dict     # maps month numbers usual number of days.  def main():    month = enteredmonth()    year = enteredyear()    is_leapyear = leapyear(year)    number_of_days = numberofdays(month)    print(month, year, "has", number_of_days, "days")  if __name__ == '__main__':     main() 

this has obvious problems - example, leap year adjustment never happens. demonstrates how capture return values functions, think main point you're struggling with.

as more advanced topic, here's how i'd using datetime built in library:

import datetime  def enteredmonth():     month = int(input("enter month in terms of number: "))     return month  def enteredyear():     year = int(input("enter year: "))     return year  def numberofdays(year, month):     first_of_entered_month = datetime.date(year, month, 1)     someday_next_month = first_of_entered_month + datetime.timedelta(days=31)     first_of_next_month = someday_next_month.replace(day=1)     last_of_entered_month = first_of_next_month - datetime.timedelta(days=1)     return last_of_entered_month.day  def main():     month = enteredmonth()     year = enteredyear()     number_of_days = numberofdays(year, month)     pretty_month_year = datetime.date(year, month, 1).strftime('%b %y')     print(pretty_month_year, "has", number_of_days, "days")