c++ - How to create an inverted triangle using only loops/control statements and two cout statements: one that outputs '#' and one that outputs '\n' -

the output supposed follows:

########  ######   ####    ## 

i have solved issue dropping 2 cout statements constraint:

#include <iostream>  void main(){ int starthash = 8; for(int row = 1; row <= 4; row++){     for(int hashnum = 1; hashnum <= starthash; hashnum++){         std::cout << "#";     }     std::cout << "\n ";     if(row == 2) std::cout << " ";     if(row == 3) std:: cout << "  ";     if(row == 4) std:: cout << "   ";     starthash -= 2; } system("pause"); } 

however, @ point can't figure out how make shape without being able output space, since cout starts @ far left , moves right. appreciated.

notice how spaces in ifs getting longer:

if(row == 2) std::cout << " "; if(row == 3) std:: cout << "  "; if(row == 4) std:: cout << "   "; 

it seems there pattern there, see if can find it. ;-)

(seeing how has 100% chance of being homework question, work it.)