text - Writing to txt in python -

i'm writing lines of numbers text file text file. numbers print while running good, when open output file nothing has been written it. can't figure out why.

min1=open(output1,"w")    oh_reader = open(filename, 'r')  countmin = 0     while countmin <=300000:         line in oh_reader:         #min1          if countmin <=60000:             hrvalue= int(line)             ibihr = line             print(line)             print(countmin)             min1.write(ibihr)             min1.write("\n")             countmin = countmin + hrvalue   min1.close() 

you should use python's with statement open files. handles closing , safer:

with open(filename, 'r') oh_reader: 

if way program indented

min1=open(output1,"w")    oh_reader = open(filename, 'r')  countmin = 0     while countmin <=300000:         line in oh_reader:             # same having pass here        #min1          if countmin <=60000:             hrvalue= int(line)             ibihr = line             print(line)             print(countmin)             min1.write(ibihr)             min1.write("\n")             countmin = countmin + hrvalue min1.close() 

the for loop empty nothing executed. fix this:

min1=open(output1,"w")  oh_reader = open(filename, 'r')  countmin = 0     while countmin <=300000:         line in oh_reader:             #min1              if countmin <=60000:                 hrvalue= int(line)                 ibihr = line                 print(line)                 print(countmin)                 min1.write(ibihr)                 min1.write("\n")                 countmin = countmin + hrvalue min1.close() 

or alternatively:

min1=open(output1,"w")  oh_reader = open(filename, 'r')  countmin = 0  line in oh_reader:     #min1      if countmin <=60000:         hrvalue= int(line)         ibihr = line         print(line)         print(countmin)         min1.write(ibihr)         min1.write("\n")         countmin += hrvalue  # += operator equal = + b min1.close()